SHALE OIL:
Exploration and
Development
Presented By: Justin Brady, Laura Kerr,
Mike Potts
Senior Capstone Project
Spring 2006
Current Energy Crisis
World’s main source of energy: Petroleum
Demand exceeding supply
April 17, 2006: Oil reaches
$70/barrel
Opportunity to develop alternate energy sources
Large economic incentive
Why Shale Oil?
Currently, United Arab Emirates hold
50% of world’s known oil reserves
How much does the
US hold?
2%
How many reserves would
be added from developing
oil shale?
2 TRILLION BARRELS
Result: US takes over as leader in the world
in oil reserves.
Outline
Introduction to Shale Oil
Project Statement
Subsurface Operations
Reservoir Temperature Profiles
Heating
Freeze Walls
Reservoir Composition Analysis
Surface Facilities
Oil/Gas Processing
Power Plant
Pipelines to Market
Production Schedule
Economics and Risk
Shale Oil: Definition
Sedimentary rock
with a high organic
content
Organic matter is
known as kerogen
Kerogen:
MW
avg.
=3000
Approximate formula
C
200
H
300
SN
5
O
11
1
1. Feng H.Y. Rates Of Pyrolysis Of Colorado shale oil. p. 732. American Institute Of Chemical Engineers Journal . Vol. 31 No. 5. 1985.
Shale Oil: History in the US
Office of Naval
Petroleum and Shale
Oil Reserves formed
in 1912
First Demonstration
mine opened outside
of Rifle, Colorado
just after World War
II
Shale Oil: History in the US
TOSCO opened an experimental mine and
production plant near Parachute, Colorado in
1960’s
Exxon opens Colony II project outside of
Parachute, Colorado in 1980
Colony Project is closed in May of 1982
Nearly 2,200 people unemployed
Loss of more than $900 million.
Project Statement
Determine which method of production of
shale oil is the most feasible.
Analyze production process to determine
Subsurface designs
Reservoir characteristics
Surface processing facilities
Scheduling of project
Pipelines
Perform an economic analysis on project.
Shale Oil Production Methods
Above Ground
Retorting
Mining of ore
Well known technology
Large environmental
impact
Popcorn effect
Large open mines
Emissions
In-Situ
Conversion
Underground
conversion
Research in progress
Lower environmental
impact
Not commercially proven
In-Situ Conversion
Currently being explored by Shell Oil
with the Mahogany Project.
Entails the heating of kerogen in the
ground and extracting the produced
hydrocarbons for further processing.
In-Situ Process Overview
Step 1: Heating
Conversion of kerogen
to oil and gas
Step 2: Freeze Wall
Construction and Water
Removal
Impermeable wall
around production site
Prevents large
environmental impact
1. Mut, Stephen. The Potential of Oil Shale. 8/20/05
In-Situ Process Overview
Step 3: Production
Products from kerogen
conversion
Step 4: Processing and
Transportation
Oil and gas separation
Pipelines to market
Schedule Table
site preparation: drilling wells, freeze wall formation, water removal
heating only
Production: refrigeration and heating continues
water injection
site reclamation
Reservoir Temperature Profile
Unsteady state 1D
temperature profile
Profile created for
Heater to heater 60
feet apart (25
heaters/acre)
1
Heat given off by
reaction accounted
for
Initial Reservoir
temperature 150
o
F
1. Bartis et. al. Oil Shale Development in the United States. Rand Santa Monica, California: 2005 p. 50
.
Reservoir Temperature Profile
Heat balance on reservoir
q
z
T
k
t
T
C
p
=
2
2
ρ
1. Guerin, Gilles 2000. Acoustic and Thermal Characterization of Oil Migration, Gas Hydrates Formation and Silica Diagenesis, PhD. Thesis,
Columbia University
Concentration due to cracking
k
RT
E
k
CAe
dt
dC
a
)(
=
Accumulation Conduction Generation
Reservoir Temperature Profile
Approximation Equation
p
rxk
RT
E
tititititti
C
HCAte
T
x
t
TT
x
t
TT
a
ρ
αα
)(
|
2
)||(||
)(
2
11
2
+
=
++
Accounts for heat of
reaction due to
cracking of kerogen
Accounts for heat spreading
linearly away from each
heater into the reservoir
rock
Temperature at
certain time and
distance between
heaters
t
T
=
2
2
z
T
α
p
C
q
ρ
Reservoir Temperature Profile
Assumptions
Thermal diffusivity assumed constant
Models only include periods of time when no fluid
flow is occurring in reservoir
Heaters assumed to be in a hexagonal pattern in the
earth
Heat generation from reaction is calculated from
average kinetic values of kerogen cracking
Heat lost to overburden by heaters not considered
Temperature vs. Reservoir Distance:
Heat of Reaction Included
0.0
200.0
400.0
600.0
800.0
1000.0
1200.0
1400.0
1600.0
0.0 10.0 20.0 30.0 40.0 50.0 60.0
Distance (ft)
Temperature (F)
3.5yr 21 months 3 year Beginning of heating 10.5 months
Reservoir Temperature Profile
Takes 3.1 years to start production of the well in
the center of the heaters.
Temperature vs. Reservoir Distance
0.0
200.0
400.0
600.0
800.0
1000.0
1200.0
1400.0
1600.0
0.0 10.0 20.0 30.0 40.0 50.0 60.0
Distance (ft)
Temperature (F)
3.5yr 21 months 3 year Beginning of heating 10.5 months
Reservoir Temperature Profile:
No Heat from Reaction
Takes 3.3 years to start production of the well in
the center of the heaters.
Reservoir Temperature Profile:
Heater to Freeze Wall
Temperature vs. Reservoir Distance:
Heater to Freeze Wall
0
200
400
600
800
1000
1200
1400
1600
0 10 20 30 40 50 60
Distance (ft)
Temperature (F)
0 hrs 10 months 24 months
48 months 72 Months 130 months
2D Reservoir Temperature
Profile
Developed using
ANSYS
Initial reservoir
temperature 150
o
F
Freeze walls
included as
boundary condition.
30 ft 30 ft30 ft 30 ft
Production wellHeater
Shale Oil:
Subsurface Operations
Drilling costs
Refrigeration costs
Pumping costs
Heating costs
Drilling Costs
Consists of wells for heaters and
producers
250 wells for heaters per 10 acre plot
80 producer wells
Total well costs of $26.4 million.
$80,000
2
per well.
2. Brown, Randy. Field Engineer XAE inc.
Freeze Wall Construction
Constructed of
double wall pipes
placed 8 ft. apart
Calcium chloride
brine at -10 degrees
F is circulated.
Water in the soil
freezes creating an
impermeable
barrier.
*Soil freeze technologies
Freeze Wall: Duty & Costs
WQ K 10*0.5
6
=
waterfreezing
M*)(**
∆Η
initialfinalp
TTCMQ
z
T
kQ
=
Purchase cost for 5.0*10
6
KW of refrigeration
1
: $12.5 million
Operating Cost
2
: $3.2 million per day
1. Peters et al p.894 fig. B-7
2. Peters et al p.898 table B-1
During freezing:
During production:
KWQ 7.8
=
Pumping
Ground water
trapped within
freeze wall
Must be
removed to
prevent
contamination
Heaters
500 ft, Shale
2000 ft,
Overburden
Producing well
Ground water
Pumping Costs
A pump is needed to remove water
from within the freeze wall.
2 barrels of water for every barrel of oil
6
Pumps must handle 1.6 million gallons per
hour to remove the water in 2 weeks.
Centrifugal pumps
80 pumps, $23,000 per pump
7
$120,000 electricity needed per day
6. Bartis et. al. Oil Shale Development in the United States. p. 50. Rand Santa Monica, California: 2005
7. Peters et. al. Plant Design And Economics For Chemical Engineers. P. 516, Mcgraw-Hill: New York 2003.
Heating: Challenges
Challenges
Regulated at a constant temperature
Must operate at high temperatures
Must have a large power output.
Heating: Solution
Overburden
Shale
Heaters
Supporting
casing
•Electric heaters
lowered to the bottom
of well hole
•Extends the entire
length of the shale
layer
2000 ft
500 ft
Heating Element
•Chromel AA* heating
element
•68% nickel
•20% chromium
•8% iron
•Self regulating:
1500
o
F
*Trademark of Hoskins Manufacturing
2 Handbook of chemical engineers, p. 4-201 8th ed.
2
Heater Design
Heating
Element
Electrical
Insulator
Steel
Casing
6”
.5”
6”
10’
•Cylindrical design
•Electric heating
element suspended
in the center.
•Spaced from the
casing by electrical
insulators
Heater Design
Heating
Element
Ceramic
Insulator
Steel
Casing
.5”
6.625
Heating Costs
Electrical
165 KW per heater
Operating at 480 V AC
and 350 amps
Electrical costs heating:
$.08 per KW-hr
4
$80,000
per day total
Materials
Steel Casing
$10 per foot
Heater element
$20 per foot
Porcelain insulator
$14 each, 250 per
heater
Total material cost:
$80,000 per heater
Reservoir Composition Study
Heating process causes
cracking of kerogen.
Estimation of composition
of products in reservoir
needed.
A temperature profile is
necessary for composition
computation
Ultimately, reservoir
characteristics will allow
design of processing
facilities.
Reservoir Composition Model
Cracking process under
the earth
Kerogen:
MW
avg.
=3000
Approximate formula
C
200
H
300
SN
5
O
11
Modeled using
visbreaking model
Using temperature
profile, predicts
concentrations of
hydrocarbons in
reservoir
Reaction depiction for thermal cracking
1
1. Castellanos, Julian. Visbreaking Yields. Encyclopedia of Chemical Processing and Design vol. 62. Marcel Dekker: New York. P411,
Composition Model
=+=
=
2
1
,
2
,
i
j
ji
n
ik
ikik
Si
KCsCsK
dt
dC
Example of hydrocarbon cracking
Reservoir Composition
Weight Fractions of Hydrocarbons During Heating
In Reservoir
0
0.2
0.4
0.6
0.8
1
C1-C5 C6-C10 C11-C15 C16-C20 C30-C40 C50-C60 C70-C280
Carbon amount in Hydrocarbons
Weight Fraction
700 F 800 F 900 F 1000 F 1100
Problems With Composition
Model
Averaged K-Values must be used due to the
large amounts of data
Parameters are fit to laboratory data that may
not be similar to reservoir
Does not account for coking in reservoir
Results are not close to reported results from
experimental site
Suggested Solution for
Composition Model
Use a tool with a larger capacity than
excel
Use a model specifically developed to
calculate products from kerogen
Example: Braun and Burnham’s model of
decomposition of kerogen
Oil Processing Design
Specifications
Oil composition
1. No significant sulfur content
2. Carbon solid from cracking is
not produced
3. Heavy hydrocarbons are not
produced
4. TBP curve of a sample light
sweet crude oil is being used
currently.
Update with compositional
model results
Production
1. 20 acres produced from one
facility
2. Water treatment will function ¼
of the time of the oil treatment
1. Bartis et. al. Oil Shale Development in the United
States. p. 50. Rand Santa Monica,
California: 2005
Oil Surface Facilities
Considerations
Elevation changes
High temperature fluid
Piping will be above
ground
Two different
transportation routes for
oil and gas
Some gas will be used
for running electricity
plant
Experimental project site
Oil Processing Skeleton Model
Oil Processing
Water processing
Oil Processing Facilities
•Inlet temperature= 680
o
F
•Inlet pressure= 1000psia
Separates C
1
- C
5
and
from heavier products
Sent to Denver
refinery for sale
Water Processing Facilities
Pumps water back
Into well
•Inlet temperature = 680
o
F
•Inlet Pressure= 1000psia
To oil
processing
Processing Facilities
Future options for gas treatment
Create a gas plant on site
Use ethane to make ethylene on site
LPG to market with oil
Burn gas production for power generation
Power Plant Options
Nuclear Power Plant
Bad public opinion
Low emissions
Gas Powered Plant
Methane is priced high
Producing methane on sight
Coal Powered Plant
High emissions
Coal supply needed
Power Plant
Combined Cycle
Capital Cost,
$500M
Operating Cost,
$60,000/day
Natural Gas
Required, 110M ft
3
Electricity
Generated, 800
MW
Efficiency, 57%
R.H. Kehlhofer, et al., Combined-Cycle Gas & Steam Turbine Power Plants
Gathering Pipelines
Well to Header
4” Schedule 80,
Carbon Steel
Oil & Gas
Header to Main
Gathering Pipe
8” Schedule 80,
Carbon Steel
Oil & Gas
Main Gathering Pipe
to Processing Facility
20” Schedule 80,
Carbon Steel
Oil & Gas
To further
collection
and
processing
Producing wells
surrounded by heaters
Header
Sell Pipelines
Gas to/from Market
8” Schedule 80, Carbon
Steel
Oil to Market
12” Schedule 80, Carbon
Steel
Gas to Power Plant
16” Schedule 80, Carbon
Steel
Pipeline Costs
Pipe Description Contents D (in) Schedule Length (ft) $/foot Total Cost
1. From Well Oil & Gas 4 80 400000 10$ 4,000,000$
2. From 1 Acre Oil & Gas 8 80 100000 30$ 3,000,000$
3. From 10 Acres Oil & Gas 20 80 1000 100$ 100,000$
4. Crude Oil to Sell Oil 24 80 1188000 110$ 130,680,000$
5. Gas to sell Gas 8 80 1188000 30$ 35,640,000$
6. Gas to Power Plant Gas 10 80 10500 40$ 420,000$
1
1
2
3
5
6
4
Total Piping Cost= $173,840,000
Production Schedule
Ten acre tracts
40,000 BPD per tract
A new tract every year
Schedule Table
site preparation: drilling wells, freeze wall formation, water removal
heating only
Production: refrigeration and heating continues
water injection
site reclamation
Environmental Effects
Location
Colorado Rocky Mountains
Lack of infrastructure
Low population
Natural habitats affected largely
Ground Coverage
Drilling cannot occur on slope
Wells spaced 30-60 ft apart
Large land clearings necessary
Emissions
Choice of power plant
Processing on site
Crude Oil Price Forecast
Crude Oil Forecasted Prices
(Price per Barrel, $US 2004)
$0.00
$10.00
$20.00
$30.00
$40.00
$50.00
$60.00
$70.00
$80.00
$90.00
2000 2005 2010 2015 2020 2025 2030 2035
Year
Dollars
Most Likely
High
Low
Natural Gas Price Forecast
Natural Gas Forecasted Prices
(Price per Thousand Cubic Feet, $US 2004)
$0.00
$1.00
$2.00
$3.00
$4.00
$5.00
$6.00
$7.00
$8.00
$9.00
2000 2005 2010 2015 2020 2025 2030 2035
Year
Dollars
Most Likely
High
Low
Pricing Estimations
Includes
• Equipment costs
• Heating
• Cooling
• Power Plant
• Drilling
• Production taxes
• Operating costs
Excludes
• Logistical costs
• Extensive Road
building
• Transporting materials
• Relocating employees
• Research costs
• Reclamation costs
Processing Equipment Costs
Component Basis of Estimation Cost
a. Heat Exchangers 5 @ $15,867 $80,000
b. Distillation D=3m, H=6m, 10 trays $87,000
c. Mixer #2 D=.508 $16,000
d. Mixer #1 D=.4572m $14,000
e. Flash #1 D=1m, H=10m $15,000
f. Pump .0544 m3/s, 6800 kPa $40,000
g. Pumps (piping) 2 w/ .151 m3/s, 1035 kPa $32,000
h. Heat Exchangers 3 w/ SA= 100 ft2 $3,600
i. Expander P=1932 kW $235,000
j. Expander #2
P=552 kW
$105,000
k. Compressor 5800 kW, centrifugal-rotary $1,100,000
$1,727,600Processing Equipment Costs
Extraction Equipment Costs
$541,067,000 Extraction Equipment Costs
$500,000,000.00
Combined Cycle,
$400/kWhd. Power Plant
$1,840,000.00
80, 1.6M gal/hr
water, 2 weeksc. Pump
$12,500,000.00800 KW capacityb. Refrigeration plant
$25,000,000.00
25/acre @
$100,000a. Heaters
Cost
Basis of
EstimationComponent
Total Capital Investment = $867 million
Component
Basis for Estimate
Cost Per Year
I. Manufacturing Cost
A. Direct Production Costs
1. Raw Materials
a. Cooling Water 178M lb/hr $0.08/1000kg $1,650,000
2. Operating Costs
a. Drilling Costs (contract) $22,400,000
b. Operating Labor $2,000,000
c. Refrigeration $0.68 per KW $196,000,000
$220,400,000
3. Direct Supervision and Clerical 15% of Operating Labor $300,000
3. Utilities (Power Plant)
a. Variable Operating Costs $86,500/day $31,572,500
b. Fixed Operating Costs $3.6M/year $3,600,000
4. Maintenance and Repair 7% of FCI $57,798,000
5. Operating Supplies 15% of Maintenance and Repair $8,670,000
6. Laboratory Charges 5% of Operating Labor $100,000
7. Patents not applicable $0
B. Fixed Charges
1. Capital Costs Straight Line Depreciation, 25 years $33,027,000
a. BLM Production Tax 12.5% of Gross $228,617,750
b. Insurance .7% of FCI $5,780,000
c. State Production Tax 1% of Gross $18,289,420
C. Overhead Costs 10% of the Total Product Cost $56,000,000
II. General Expenses
A. Administration Costs 20% of Operating labor and maintenance $11,960,000
Total Annual Cost
$677,800,000
Total
Annual Costs
Cost per barrel: $23.21
Profit Estimates
Input picture of cash flow position thing!!!!!
Payback period:
9.7 years
Cash Flow at 25 years:
$9.7 billion
NPV at 8%:
$1.5 billion
Return on Investment:
162%
Risk Assessment
Distribution for NPV / Net Income/G30
Values in 10^ -10
Values in Billions
0.000
0.500
1.000
1.500
2.000
2.500
Mean=1.485529E+09
-6 -4 -2 0 2 4 6 8 10-6 -4 -2 0 2 4 6 8 10
5% 90% 5%
-1.4391 4.3723
Mean=1.485529E+09
Distribution for Total / ROI/F29
0.000
0.200
0.400
0.600
0.800
1.000
Mean=0.9269187
-2 -1 0 1 2 3 4-2 -1 0 1 2 3 4
5% 90% 5%
-.1468 1.9868
Mean=0.9269187
Risk Assessment
Future Work
Logistics
Transportation of materials
Drilling complications
Reclamation Process
Work Force
Optimizations
Heater to heater distances
Heater temperature
Heater material
Composition of reservoir
3D temperature profile
Detailed project risk assessment
Questions?
Net Present Values:
Varied Rates
Rate NPV (25 years)
0.08 $1.5 billion
0.10 $0.8 billion
0.12 $0.4 billion
0.15 $-0.1 billion
Risk Assessment:
NPV with Rate=10%
Distribution for NPV / Net Income/G30
Values in Billions
0.000
0.200
0.400
0.600
0.800
1.000
Mean=8.349873E+08
-6 -4 -2 0 2 4 6 8
-1.4-1.4-1.4-1.4
-6 -4 -2 0 2 4 6 8
4.99% 90.01% 5%
-1.4 3.0769
Mean=8.349873E+08 Mean=8.349873E+08
Risk Assessment:
NPV with Rate=12%
Distribution for NPV / Net Income/G30
Values in Billions
0.000
0.200
0.400
0.600
0.800
1.000
Mean=3.687469E+08
-4 -3 -2 -1 0 1 2 3 4 5-4 -3 -2 -1 0 1 2 3 4 5
5% 90% 5%
-1.3767 2.1075
Mean=3.687469E+08
Risk Assessment:
NPV with Rate=15%
Distribution for NPV / Net Income/G30
Values in Billions
0.000
0.200
0.400
0.600
0.800
1.000
Mean=-1.012595E+08
-4 -3 -2 -1 0 1 2 3 4-4 -3 -2 -1 0 1 2 3 4
5% 90% 5%
-1.3296 1.1296
Mean=-1.012595E+08
Temperature Profile:
Affect of Thermal Diffusivity
Thermal Diffusivity vs. Time
0
20000
40000
60000
80000
100000
0.003 0.008 0.013
Thermal Diffusivity (ft^2/hr)
Time
(hrs)
40 ft 50 ft 60 ft 30 ft 70 ft
Temperature Profile:
Affect of Heater Distance
Heater Distance vs. Time
0
20000
40000
60000
80000
100000
25 35 45 55 65 75
Heater Distance (ft)
Time (hrs)
.004 ft^2/hr .008 ft^2/hr .016 ft^2/hr
Reservoir Production:
Fracturing
Reservoir
Heater
Water and
Sand
Heater